My brother is in 6th grade and needs help with his math. I tried to help but I can't find any answers on it.
Accepted Solution
A:
Answer: Question 1) 17.4Question 2) 1.7Question 3) 2.8Question 4) 8.6Step-by-step explanation:Mean absolute deviation is the average distance between the data points from the set to the mean point of the data set. It shows the variability in data or how much the data points are spread.method to calculate Mean absolute deviation:a. calculate mean b. calculate absolute deviation of each data pointc. add all the deviationsd. divide absolute deviation by number of pointsmean absolute deviation = ∑l[tex]x_{i}[/tex]-xl / nThe given problem has four sub-partsSolution 1:Mean= (78+99+90+80+55+56+102+88+60+42)/10 = 750/10 = 75Mean absolute deviation= ( I 78-75 I + I 99-75 I+I 90-75 I + I 80-75 I + I 55-75 I + I 56-75 I + I 102-75 I + I 88- 75 I + I 60-75 I + I 42-75 I) /10 = (174)/10 = 17.4Solution 2: Mean = (10+13+7+12+9+8+12+10+11+13)/10 = (105)/10 = 10.5Mean absolute deviation = ( I 10-10.5 I + I 13-10.5 I + I 7-10.5 I + I 12-10.5 I + I 9-10.5 I + I 8-10.5 I + I 12-10.5 I + I 10-10.5 I + I 11-10.5 I + I 3-10.5 I) /10 = 17/10 = 1.7Solution 3:Mean= (1+7+10+5+3+3+6+12+9+4)/10 = 60/10 = 6Mean absolute deviation = ( I 1-6 I + I 7-6 I + I 10-6 I + I 5-6 I + I 3-6 I + I 3-6 I + I 6-6 I + I 12- 6 I + I 9-6 I + I 4-6 I) /10 = (28)/10 = 2.8Solution 4:Mean= (30+46+25+45+18+25+15+32+40+24)/10 = 300/10 = 30Mean absolute deviation = ( I 30-30 I + I 46-30 I + I 25-30 I + I 45-30 I + I 18-30 I + I 25-30 I + I 15-30 I + I 32-30 I + I 40-30 I + I 24-30 I) /10 = (86)/10 = 8.6!